4(y-3)=3[y+2(y-2)]

Solution for 4(y-3)=3[y+2(y-2)] equation:

Simplifying
4(y + -3) = 3[y + 2(y + -2)]

Reorder the terms:
4(-3 + y) = 3[y + 2(y + -2)]
(-3 * 4 + y * 4) = 3[y + 2(y + -2)]
(-12 + 4y) = 3[y + 2(y + -2)]

Reorder the terms:
-12 + 4y = 3[y + 2(-2 + y)]
-12 + 4y = 3[y + (-2 * 2 + y * 2)]
-12 + 4y = 3[y + (-4 + 2y)]

Reorder the terms:
-12 + 4y = 3[-4 + y + 2y]

Combine like terms: y + 2y = 3y
-12 + 4y = 3[-4 + 3y]
-12 + 4y = [-4 * 3 + 3y * 3]
-12 + 4y = [-12 + 9y]

Add '12' to each side of the equation.
-12 + 12 + 4y = -12 + 12 + 9y

Combine like terms: -12 + 12 = 0
0 + 4y = -12 + 12 + 9y
4y = -12 + 12 + 9y

Combine like terms: -12 + 12 = 0
4y = 0 + 9y
4y = 9y

Solving
4y = 9y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-9y' to each side of the equation.
4y + -9y = 9y + -9y

Combine like terms: 4y + -9y = -5y
-5y = 9y + -9y

Combine like terms: 9y + -9y = 0
-5y = 0

Divide each side by '-5'.
y = 0

Simplifying
y = 0